7 free football betting schemes

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It is also called Martingale scheme. It begins with a single bet of 1$ and put on a odd (1 or 2, because at X, the rate is 3.20 and it's risky) to 2.50 , if you lose, you must to put 2$ on another game with 2.50 and if you cought that match you recover money and you also gain some extra money.

This is the scheme :

1$ - if you caught the match, you win 2.50$ and if you lose the match you put 2$ on another match

2$ - if you caught the match, you win 5$ and if you lose the match you put 4$ on another match

4$ - if you caught, win 10$ and if you lose put 8$ on another match

8$ - if you caught, win 20$ and if you lose put 16$ on another match

16$ - if you caught, win 40$ and if you lose put 32$ on another match

32$ - if you caught, win 80$ and if you lose put 64$ on another match

64$ - if you caught, win 160 and if you lose put 128$ on another match

128$ - if you caught, win 320$ and if you lose put 256$ on another match

256$ - if you caught, win 640$ and if you lose put 512$ on another match

If you caught one ticket, you must to restart again with 1$ ... 2$ ... 4$ until if you caught one ticket again.

Now i will explain how much you win if you lose 9 consecutive matches and won the 10th match.

1$         - lost match

2$         - lost match

4$         - lost match

8$         - lost match

16$        - lost match

32$        - lost match

64$        - lost match

128$       - lost match

256$       - lost match

512$       - winning match

You invested so far: 1$ +2$ +4$ +8$ +16$ +32$ +64$ +128$ +256$ +512$ = 1023$ and you won from winning ticket number 10: 512$ x 2.5 = 1280$. So if you win only the 10-th match , you win 1280-1023=257$

For this reason, you must to have money to invest in this scheme and you need luck, but also some strategy to choose the correct matches for this scheme.